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144=36x-x^2
We move all terms to the left:
144-(36x-x^2)=0
We get rid of parentheses
x^2-36x+144=0
a = 1; b = -36; c = +144;
Δ = b2-4ac
Δ = -362-4·1·144
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-12\sqrt{5}}{2*1}=\frac{36-12\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+12\sqrt{5}}{2*1}=\frac{36+12\sqrt{5}}{2} $
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